Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be : (Take specific heat of water =1 cal g-1
(CO)-1 and latent heat of steam = 540 cal g-1)
Heat lost = Heat gained
Total mass of water = (20 + 2.5) g = 22.5 g