First slide

Questions based on phase change

Question

Steam at 100⁰C is passed into 20 g of water at 10⁰C. When water acquires a temperature of 80⁰C, the mass of water present will be [Take specific heat of water 1 cal g^–1 c^–1 latent heat of steam = 540 cal/g^-1]

Moderate

A

31.5 g
B

42.5 g
C

22.5 g
D

24 g

Solution

Let x gm of steam be converted into water.
x(540) + x(1)(100-80) = 20(80 - 10) ⇒ x (560) = 1400
x = 2.5 gm, mass of water = 22.5gm

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