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Steam at 100°C  is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be [Take specific heat of water = 1 cal g-1oC and latent heat of steam = 540 cal g-1 ]

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24 g
31.5 g
42.5 g
22.5 g

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detailed solution

Correct option is D

Here,  Specific heat of water, sw=1 cal g−1∘C−1 Latent heat of steam, Ls=540 cal g−1 Heat lost by mg of steam at 100∘C to change into water  at 80∘C is Q1=mLs+mswΔTw=m×540+m×1×(100−80)=540m+20m=560m Heat gained by 20g of water to change its temperature  from 10∘C to 80∘C is Q2=mwswΔTw=20×1×(80−10)=1400 According to principle of calorimetry  Q1=Q2∴ 560m=1400 or  m=2.5gTotal mass of water present =(20+m)g=(20+2.5)g=22.5g

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Similar Questions

Consider the following statements.
(A) The steam at 100°C causes more severe burn to human body than the water at 100°C.
(B) The steam has greater internal energy than water due to latent heat of vaporization.
Select the correct option.
(a) (A) is false but (B) is true.
(b) Both (A) and (B) are true.
(c) (A) is true but (B) is false.
(d) Both (A) and (B) are false. 

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