Steam at $$100oc$$ is passed into $$1.1$$ g of water contained in a calorimeter of water equivalent $$0.02$$ g at $$15oC$$ till the temperature of the calorimeter and its contents rises to $$80oC$$. The mass of the steam condensed in g is

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Heat is lost by steam in two stages: (i) for change of state from steam at $$100oC$$ to water at $$100oC$$ is m x $$540(ii)$$ to change water at $$100oC$$ to water at $$80oC$$ is m × $$1$$ × (100$$ $$-$$ $$80), where m is the mass of steam condensed.Total heat lost by steam is m × $$540$$ $$+$$ m × $$20$$ $$=$$ $$560m$$ (cals) Heatgained by calorimeter and its contents $$is=(1.1+0.02)$$×$$(80$$−$$15)=1.12$$×$$65$$ cals using Principle of calorimetery, Heat gained $$=$$ heat lost∴$$560m=1.12$$×$$65$$ ⇒$$m=0.130gm$$

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