First slide

Calorimetry

Question

Steam at 100^oc is passed into 1.1 g of water contained in a calorimeter of water equivalent 0.02 g at 15^oC till the temperature of the calorimeter and its contents rises to 80^oC. The mass of the steam condensed in g is

Moderate

A

0.130
B

0.065
C

0.260
D

0.135

Solution

Heat is lost by steam in two stages:
(i) for change of state from steam at 100^oC to water at 100^oC is m x 540
(ii) to change water at 100^oC to water at 80^oC is m $\times$ 1 $\times$ (100 - 80), where m is the mass of steam condensed.
Total heat lost by steam is m $\times$ 540 + m $\times$ 20 = 560m (cals) Heat
gained by calorimeter and its contents is
$= (1 .1 + 0 .02) \times (80 - 15) = 1 .12 \times 65 cals$
using Principle of calorimetery, Heat gained = heat lost
$∴ 560 m = 1 .12 \times 65 \Rightarrow m = 0 .130 gm$

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