First slide

Questions based on phase change

Question

Steam is passed into 54 g of water at 30°C till the temperature of the mixture becomes 90°C. If the latent heat of steam is 536 cal/g, the mass of the mixture will be:

Moderate

A

80 g
B

60 g
C

50 g
D

24 g

Solution

Let mass of steam be m then
$m \times 536 + m \times 1 \times (100 - 90) = 54 \times 1 \times (90 - 30) \Rightarrow m = 5.93 g \approx 6 g Total mass of mixture = 54 + 6 = 60 g .$

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