Questions
Steam is passed into 54 gm of water at 30°C till the temperature of mixture becomes 90°C. If the latent heat of steam is 536 cal/gm, the mass of the mixture will be
detailed solution
Correct option is B
Let mass of steam condensed = M gmM x 536 + M×1×(100-90)= 54×1×(90-30)Mx536 = 54x60M = 54×60536 = 5.5 gmHence, mass of mixture = 54 + 5.5 = 59.5 gm.Talk to our academic expert!
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We can get vapour state of a substance through the process of:
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(iv) regelation
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