Questions

# The steam point and the ice point of a mercury thermometer are marked as  ${80}^{0}$ and  ${20}^{0}$. What will be the temperature in centigrade mercury scale when this thermometer reads ${32}^{0}$

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By Expert Faculty of Sri Chaitanya
a
200C
b
300C
c
100C
d
00C
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detailed solution

Correct option is A

relation between centigrade thermometer and unknown thermometer is C100=X−LFPUFP−LFP C is reading on centigrade thermometer;X  is reading on unknwn thermometer=32 LFP is lower fixed point=20;UFP is upper fixed point=80 substitute given values in above relation ⇒C100=32−2080−20 ⇒C100=1260 ⇒C=1206=200C

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