A steel ball is dropped on a hard surface from a height of 1 m and rebounds to a height of 64 cm. The maximum height attained by the ball after nth bounce is (in m)

hn= (e2n)hiGiven thatfinal height rise h2=64cm,initial height of ball h1=100cm,number of collisions n=1 h2= (e2)h1 (64 cm) = (e2)(100cm)                                  ∴ e =    0.8            Substituting in Eq.(i) we have hn= (0.8)2n(1m)hn=(0.8)2n