First slide

Viscosity

Question

A steel ball of radius 2 mm of relative density 8 .2 is falling through a liquid of relative density 1.9. Its terminal velocity is 0.7 m/s. What is the viscosity of the liquid if acceleration due to gravity is 10 m/s² ?

Easy

A

8 x 1O-2 PI
B

8 PI
C

8 x 10 ^-2 P
D

8 P

Solution

$η = \frac{2}{9} \frac{(ρ - σ) r^{2}}{v} g H e r o ρ = 8 \cdot 2 \times 10^{3} k g / m^{3} σ = 1 \cdot 9 \times 10^{3} k g / m^{3}, r = 2 m m a n d V = 0 \cdot 7 m / s ∴ η = 8 \times 10^{- 2} P I$

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