A steel ball of radius 2 mm of relative density 8 .2 is falling through a liquid of relative density 1.9. Its terminal velocity is 0.7 m/s. What is the viscosity of the liquid if acceleration due to gravity is 10 m/s2 ?

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8 x 1O-2 PI

8 PI

8 x 10 -2 P

8 P

answer is A.

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Detailed Solution

η=29(ρ−σ)r2vg Hero ρ=8⋅2×103kg/m3 σ=1⋅9×103kg/m3,r=2mm and V=0⋅7m/s ∴ η=8×10−2PI

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