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A steel ball is suspended in an accelerating cabin by two cords A and B. If the acceleration of the frame is a=g33, then the tension in A is x times the tension in B. Find x.

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Detailed Solution

T1sin⁡60∘+T2sin⁡60∘=mgT1+T2=23mgm×g33=T2cos⁡60∘−T1cos⁡60∘T2−T1=2mg33Solving we get,T1=2mg33,T2=4mg33Note: Here ma is pseudo force

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