First slide

Thermal expansion

Question

A steel meter scale is to be ruled so that millimeter intervals are accurate within about 5 ×10^–5 m at a certain temperature. The maximum temperature variation allowable during the ruling is [coefficient of linear expansion of steel = 10 ×10^–6k^–1]

Easy

A

2⁰C
B

5⁰C
C

7⁰C
D

10⁰C

Solution

$\large \alpha=\frac {\Delta l}{l\Delta t}\Rightarrow \Delta t=\frac {\Delta l}{l\alpha}=\frac {5\times 10^{-5}\times 10^{-3}}{1\times 10^{-3}\times 10^{-5}}=5^0C$

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