A steel ring of radius r and cross-sectional area A is fitted on to a wooden disc of radius R (R > r). IfYoung's modulus of the steel is Y, then the force with which the steel ring is expanded is
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a
AYr(R−r)
b
Y(R−r)r
c
AY(R−r)R
d
AY(R−r)r
answer is D.
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Detailed Solution
Change in length of ring = 2πR−2πrLongitudinal strain =2πR−2πr2πr=R−rrYoung's modulus, Y=F/AR−rr⇒ Y=FrA(R−r)⇒F=YA(R−r)r