First slide

Thermal expansion

Question

A steel rod of length 4cm and cross-sectional area 4cm² is tightly fixed between two supports and is not allowed to expand. It is heated through 2°C. Thermal stress developed is ....10⁶ N/m² (Y= 20 ×10¹⁰N/m² = 18 × 10^–6/⁰C)

Easy

A

7.2
B

2.7
C

3.6
D

0.72

Solution

Thermal stress $\large \frac FA=Y\alpha\Delta t$
$\large \frac FA=20\times 10^{10}\times 18\times 10^{-6}\times 2=7.2\times 10^6N/m^2$

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