'A' is a steel rod of length IA and 'B' a copper rod of length lB. Values of lA and lB such that lA -lB = 5 cm at all temperatures, are :(Given αCu=1.7×10-5/C o,αsteel=1.1×10-5/C o)
21.4 cm, 16.4 cm
10.8 cm, 5.8 cm
14.2 cm, 9.2 cm
32.4 cm, 27.4 cm
lA'-lB' =lA(1+αA∆T)-lB(1+αB∆T)=constant ⇒ lAαA=lBαB ⇒ 11lA=17lB Also lA-lB=5 So lA=14.2 cm and lB =9.2 cm