First slide
Thermal expansion
Question

'A' is a steel rod of length IA and 'B' a copper rod of length lB. Values of lA and lB such that lA -lB = 5 cm at all temperatures, are :
(Given αCu=1.7×10-5/C  o,αsteel=1.1×10-5/C  o)

Moderate
Solution

lA'-lB' =lA(1+αAT)-lB(1+αBT)=constant            lAαA=lBαB            11lA=17lB Also          lA-lB=5 So                     lA=14.2 cm and                   lB =9.2 cm       

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