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'A' is a steel rod of length I_A and 'B' a copper rod of length l_B. Values of l_A and l_B such that l_A -l_B = 5 cm at all temperatures, are :
(Given $α_{Cu} = 1.7 \times 10^{- 5} / {}^{o}C, α_{st e e l} = 1.1 \times 10^{- 5} / {}^{o}C$ )

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21.4 cm, 16.4 cm

10.8 cm, 5.8 cm

14.2 cm, 9.2 cm

32.4 cm, 27.4 cm

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detailed solution

Correct option is C

lA'-lB' =lA(1+αA∆T)-lB(1+αB∆T)=constant ⇒ lAαA=lBαB ⇒ 11lA=17lB Also lA-lB=5 So lA=14.2 cm and lB =9.2 cm

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'A' is a steel rod of length IA and 'B' a copper rod of length lB. Values of lA and lB such that lA -lB = 5 cm at all temperatures, are :(Given αCu=1.7×10-5/C o,αsteel=1.1×10-5/C o)

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Ready to Test Your Skills?

free study material

'A' is a steel rod of length I_A and 'B' a copper rod of length l_B. Values of l_A and l_B such that l_A -l_B = 5 cm at all temperatures, are :
(Given $α_{Cu} = 1.7 \times 10^{- 5} / {}^{o}C, α_{st e e l} = 1.1 \times 10^{- 5} / {}^{o}C$ )