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A steel rod of length 5 m is fixed rigidly between two supports. α  of steel  =12×106/oCY=2×1011Nm2  With the increase in its temperature by 400C . the stress developed in the rod is

a
9.6×105Nm−2
b
9.6×106Nm−2
c
9.6×107Nm−2
d
9.6×108Nm−2

detailed solution

Correct option is C

FA=YαΔt=2×1011×12×10−6×40=24×4×106=96×106N/m2=9.6×107N/m2

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