A steel rod of length 1 m and radius 10 mm is stretched by a force 100 kN along its length. The stress produced in the rod is YSteel =2×1011Nm−2
3.18×106Nm−2
3.18×107Nm−2
3.18×108Nm−2
3.18×109Nm−2
Here, r=10mm=10×10−3=10−3m
L=1m,F=100kN=100×103N=105N
Stress produced in the rod is
Strain = FA=Fπr2=100×103N3.14×10−2m2
=3.18×108Nm−2