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Q.

A steel rod of length 1 m and radius 10 mm is stretched by a force 100 kN along its length. The percentage strain produced in the rod is Ysteel = 2×1011 Nm-2

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a

0.04%

b

0.08%

c

0.16%

d

0.24%

answer is C.

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Detailed Solution

Elongation,ΔL=(F/A)LY=3.18×108Nm−2(1m)2×1011Nm−2     =1.59×10−3m=1.59mmStrain produced in the rod isStrain =ΔLL=1.59×10−3m1m=1.59×10−3=0.16%
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