First slide

Special cases

Question

A steel sphere of mass 100 gm moving with a velocity of 4 m/s collides with a dust particle elastically moving in the same direction with a velocity of 1 m/s. The velocity of the dust particle after the collision is (dust particle is of negligible mass)

Moderate

A

8 m/s
B

7 m/s
C

6 m/s
D

9 m/s

Solution

Conserving Linear momentum ,
0.1 X V₁ + m X V₂ = 0.1 X 4
⇒ V₁ + 10 m V₂ = 4 - - - - - - - - - - (1)
Also , V₂ -V₁ / 4-1 = e =1
⇒ V₁ = (V₂ - 3 )-----------------(2)
From (1) and (2) , V₂ = 7 / (1 +10 m) m/s
Since m can be ignored , V₂ $\large \simeq$ 7 m/s

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