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Q.

A steel sphere of mass 100 gm moving with a velocity of 4 m/s collides with a dust particle elastically moving in the same direction with a velocity of 1 m/s. The velocity of the dust particle after the collision is (dust particle is of negligible mass)

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a

8 m/s

b

7 m/s

c

6 m/s

d

9 m/s

answer is B.

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Detailed Solution

Conserving Linear momentum ,0.1 X V1 + m X V2 = 0.1 X 4⇒ V1 + 10 m V2 = 4 - - - - - - - - - - (1)Also , V2 -V1 / 4-1 = e =1 ⇒ V1 = (V2 - 3 )-----------------(2)From (1) and (2) , V2 = 7 / (1 +10 m) m/sSince m can be ignored , V2 7 m/s
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