Download the app

Questions  

A steel sphere of mass 100 gm moving with a velocity of 4 m/s collides with a dust particle elastically moving in the same direction with a velocity of 1 m/s. The velocity of the dust particle after the collision is (dust particle is of negligible mass)

a
8 m/s
b
7 m/s
c
6 m/s
d
9 m/s

detailed solution

Correct option is B

Conserving Linear momentum ,0.1 X V1 + m X V2 = 0.1 X 4⇒ V1 + 10 m V2 = 4 - - - - - - - - - - (1)Also , V2 -V1 / 4-1 = e =1 ⇒ V1 = (V2 - 3 )-----------------(2)From (1) and (2) , V2 = 7 / (1 +10 m) m/sSince m can be ignored , V2 7 m/s

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

In the elastic collision of a heavy vehicle moving with a velocity of 10 m s-1 and a small stone at rest, the stone will fly away with a velocity equal to


phone icon
whats app icon