Questions
A steel sphere of mass 100 gm moving with a velocity of 4 m/s collides with a dust particle elastically moving in the same direction with a velocity of 1 m/s. The velocity of the dust particle after the collision is (dust particle is of negligible mass)
detailed solution
Correct option is B
Conserving Linear momentum ,0.1 X V1 + m X V2 = 0.1 X 4⇒ V1 + 10 m V2 = 4 - - - - - - - - - - (1)Also , V2 -V1 / 4-1 = e =1 ⇒ V1 = (V2 - 3 )-----------------(2)From (1) and (2) , V2 = 7 / (1 +10 m) m/sSince m can be ignored , V2 7 m/sTalk to our academic expert!
Similar Questions
In the elastic collision of a heavy vehicle moving with a velocity of 10 m s-1 and a small stone at rest, the stone will fly away with a velocity equal to
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests