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A steel sphere A of mass m, moving with velocity 4 m/s, collides elastically and obliquely with another identical stationary steel sphere B. After the impact sphere B starts moving with velocity V making an angle of 60o with the original direction of sphere A. Find V.

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Detailed Solution

After the impact, velocity vectors of the spheres will be mutually perpendicular,Conserving Momentum, mV'sin300 = mVsin600 ⇒ V' = 3 V .......(1)and mVcos600 + mV'cos300= m × 4 ⇒ V+ 3 V'=8 .......(2)Solving, we get V = 2 m/s.

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A steel sphere A of mass m, moving with velocity 4 m/s, collides elastically and obliquely with another identical stationary steel sphere B. After the impact sphere B starts moving with velocity V making an angle of 60o with the original direction of sphere A. Find V.