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The steps in collision

Question

A steel sphere A of mass m, moving with velocity 4 m/s, collides elastically and obliquely with another identical stationary steel sphere B. After the impact sphere B starts moving with velocity V  making an angle of 60o  with the original direction of sphere A. Find V.

Moderate
Solution

After the impact, velocity vectors of the spheres will be mutually perpendicular,

Conserving Momentum, 

mV'sin300=mVsin600       V'=3  V   .......(1)andmVcos600+mV'cos300=   m  ×  4       V+3  V'=8    .......(2)

Solving, we get V = 2 m/s.



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