Q.

A steel sphere A of mass m, moving with velocity 4 m/s, collides elastically and obliquely with another identical stationary steel sphere B. After the impact sphere B starts moving with velocity V  making an angle of 60o  with the original direction of sphere A. Find V.

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answer is 3.

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Detailed Solution

After the impact, velocity vectors of the spheres will be mutually perpendicular,Conserving Momentum, mV'sin300 = mVsin600  ⇒     V' = 3  V   .......(1)and mVcos600 + mV'cos300=   m  ×  4  ⇒     V+ 3  V'=8    .......(2)Solving, we get V = 2 m/s.
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A steel sphere A of mass m, moving with velocity 4 m/s, collides elastically and obliquely with another identical stationary steel sphere B. After the impact sphere B starts moving with velocity V  making an angle of 60o  with the original direction of sphere A. Find V.