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Q.

A steel sphere A is at rest on a frictionless horizontal surface. Another identical sphere B moving with velocity 2m/s collides head on with A. If coefficient of restitution e = 0.5, fraction of kinetic energy of B lost in the process is

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a

15/16

b

3/4

c

1/8

d

1/4

answer is A.

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Detailed Solution

Conserving momentum: mv= mv1+mv2 where v1 is the final velocity of B while v2 is the final velocity of Av2-v1= v2Putting above value in first equation, we getv2=3v1v1=v4 v2=3v4   Change in kinetic energy of B = 1532mv2Thus fraction of KE lost= 1516
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A steel sphere A is at rest on a frictionless horizontal surface. Another identical sphere B moving with velocity 2m/s collides head on with A. If coefficient of restitution e = 0.5, fraction of kinetic energy of B lost in the process is