A steel wire of cross sectional area 2mm2 is just stretched horizontally between two fixed points at a temperature of 350C . The temperature of the wire changed to 250C . Then (Coefficient of linear expansion of steel=11×10−6/0C; Ysteel=2×1011Nm−2 )

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The thermal strain is 11×10−5

The thermal stress is 2.2×107N/m2

The tension in the wire at temperature 250C is 44N

All the above

answer is D.

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Detailed Solution

Thermal strain(eℓ)=αΔt Thermal stress = y x thermal strain ⇒FA=yeℓ Tension (Mg) = yπr2(eℓ)

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