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A steel wire of cross sectional area $2 m m^{2}$ is just stretched horizontally between two fixed points at a temperature of $35^{0} C$ . The temperature of the wire changed to $25^{0} C$ . Then (Coefficient of linear expansion of steel $= 11 \times 10^{- 6} /^{0} C; Y_{s t e e l} = 2 \times 10^{11} N m^{- 2}$ )

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The thermal strain is 11×10−5

The thermal stress is 2.2×107N/m2

The tension in the wire at temperature 250C is 44N

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detailed solution

Correct option is D

Thermal strain(eℓ)=αΔt Thermal stress = y x thermal strain ⇒FA=yeℓ Tension (Mg) = yπr2(eℓ)

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A steel wire of cross sectional area 2mm2 is just stretched horizontally between two fixed points at a temperature of 350C . The temperature of the wire changed to 250C . Then (Coefficient of linear expansion of steel=11×10−6/0C; Ysteel=2×1011Nm−2 )

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