A steel wire of cross-sectional area 3×10−8m2 can withstand a maximum strain of 10-3, Young's modulus of steel is 2×1011Nm−2. The maximum mass this wire can hold is

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40 kg

60 kg

80 kg

100 kg

answer is B.

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Detailed Solution

Maximum stress = Y x (Maximum strain) MgA=2×1011×10−3=2×108Nm−2⇒ Maximum mass of this wire, M=2×108×3×10−810=60kg

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