First slide

Stress and strain

Question

A steel wire of cross-sectional area $3 \times 10^{- 8} m^{2}$ can withstand a maximum strain of 10^-3, Young's modulus of steel is $2 \times 10^{11} {Nm}^{- 2} .$ The maximum mass this wire can hold is

Moderate

A

40 kg
B

60 kg
C

80 kg
D

100 kg

Solution

Maximum stress = Y x (Maximum strain)
$\begin{array}{l} \frac{Mg}{A} = 2 \times 10^{11} \times 10^{- 3} = 2 \times 10^{8} {Nm}^{- 2} \\ \Rightarrow Maximum mass of this wire, \\ M = \frac{2 \times 10^{8} \times 3 \times 10^{- 8}}{10} = 60 kg \end{array}$

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