Q.

A steel wire of cross-sectional area 2mm2 and Young’s modulus 2 x1011N / m2 is stretched longitudinally by a force of 200 N. The elastic potential energy stored per unit volume in the string is n × 104. Find the value of ‘n’.

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answer is 00002.50.

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Detailed Solution

EPE per unit volume =12 × stress× strain =stress22Y=F22YA2=20022×2×1011×4×10-12J/m3=2.5×104 J/m3

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A steel wire of cross-sectional area 2mm2 and Young’s modulus 2 x1011N / m2 is stretched longitudinally by a force of 200 N. The elastic potential energy stored per unit volume in the string is n × 104. Find the value of ‘n’.