First slide

Elastic Modulie

Question

A steel wire of cross-sectional area 3 x 10^-6 m² can withstand a maximum strain of 10^-3, Young's modulus of steel is 2 X 10¹¹ Nm^-2. The maximum mass this wire can hold is

Moderate

A

40 kg
B

60 kg
C

80 kg
D

100 kg

Solution

Maximum stress = Y x (Maximum strain)
$\frac{M g}{A} = 2 \times 10^{11} \times 10^{- 3} = 2 \times 10^{8} {Nm}^{- 2}$
$\Rightarrow$ Maximum mass of this wire,
$M = \frac{2 \times 10^{8} \times 3 \times 10^{- 6}}{10} = 60 kg$

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