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Q.

A steel wire of cross-sectional area 3 x 10-6 m2 can withstand a maximum strain of 10-3, Young's modulus of steel is 2 X 1011 Nm-2. The maximum mass this wire can hold is

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a

40 kg

b

60 kg

c

80 kg

d

100 kg

answer is B.

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Detailed Solution

Maximum stress = Y x (Maximum strain)MgA=2×1011×10−3=2×108Nm−2⇒  Maximum mass of this wire,M=2×108×3×10−610=60kg
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