A steel wire of length 20cm is stretched to increase its length by 0.2 cm. the lateral strain due to contraction in the wire was found to be 0.0019. Then Poisson’s ratio for steel is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
0.0038
b
0.38
c
−0.19
d
0.19
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Poisson’s ratio (σ)=-Δrr(Δℓℓ) =-0.00190.220 =-0.19
A steel wire of length 20cm is stretched to increase its length by 0.2 cm. the lateral strain due to contraction in the wire was found to be 0.0019. Then Poisson’s ratio for steel is