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A steel wire of length I and cross-section area A is stretched by 1 cm under a given load. When the same load is applied to another steel wire of double its length and half of its cross-section area, the amount of stretching is

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a

0.5 cm

b

2 cm

c

4 cm

d

1.5 cm

answer is C.

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Detailed Solution

We know that, Δl=FLAYHere, Δl∝LAAccording to question, Δl1Δl2=L1L2×A2A1⇒ Δl1Δl2=12×12⇒Δl1Δl2=14⇒ Δl2=4Δl1⇒Δl2=4×1=4cm

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