A steel wire of length 1.5 m and diameter 0.5 mm is stretched by applying a weight of 1 kg wt. Then find the increase in the length of wire (Y=2×1011 Nm–2)

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0.2743 mm

0.3743 mm

0.1743 mm

0.4743 mm

answer is B.

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Detailed Solution

y=FℓAe⇒e=FℓAY=mgℓYπr2=1×101.52×1011×3.1414×10-32=0.3743mm

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