A steel wire of length $$2$$ m and $$1.2$$×$$10$$−$$7m2$$ in $$cross-sectional$$ area is stretched by a force of $$36$$ N. Calculate the work done in ×$$10$$−$$2J$$ stretching the wire $$Y=1.8$$×$$1011N/m2$$.

Question

A steel wire of length $$2$$ m and $$1.2$$×$$10$$−$$7m2$$ in $$cross-sectional$$ area is stretched by a force of $$36$$ N. Calculate the work done  in ×$$10$$−$$2J$$ stretching the wire $$Y=1.8$$×$$1011N/m2$$.

Infinity Learn · Accepted Answer

The stress in steel wire σ$$=FA=361.2$$×$$10$$−$$7=3$$×$$108N/m2As$$ Young's modulus of elasticity, $$Y=$$ Stress  Strain Strain $$=$$ stress $$Y=3$$×$$1081.8$$×$$1011=53$$×$$10$$−$$3Workdone$$ $$=12($$ stress $$)($$ strain $$)$$ volume                   $$=12$$×$$3$$×$$108$$×$$53$$×$$10$$−$$32$$×$$1.2$$×$$10$$−$$7=6$$×$$10$$−$$2$$ Joule.

Elastic behaviour of solids

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A steel wire of length 2 m and $1.2 \times 10^{- 7} m^{2}$ in cross-sectional area is stretched by a force of 36 N. Calculate the work done $(in \times 10^{- 2} J)$ stretching the wire $(Y = 1 .8 \times 10^{11} N / m^{2})$ .

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Elastic behaviour of solids

Remember concepts with our Masterclasses.

A steel wire of length 2 m and 1.2×10−7m2 in cross-sectional area is stretched by a force of 36 N. Calculate the work done in ×10−2J stretching the wire Y=1.8×1011N/m2.

The stress in steel wire σ=FA=361.2×10−7=3×108N/m2As Young's modulus of elasticity, Y= Stress Strain Strain = stress Y=3×1081.8×1011=53×10−3Workdone =12( stress )( strain ) volume =12×3×108×53×10−32×1.2×10−7=6×10−2 Joule.

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A steel wire of length 2 m and $1.2 \times 10^{- 7} m^{2}$ in cross-sectional area is stretched by a force of 36 N. Calculate the work done $(in \times 10^{- 2} J)$ stretching the wire $(Y = 1 .8 \times 10^{11} N / m^{2})$ .