First slide

Stress and strain

Question

For steel $Y = 2 \times 10^{11} {Nm}^{- 2}$ , then the force required to double the length of a steel wire of area 1 cm² is

Moderate

A

$2 \times 10^{7} N$
B

$2 \times 10^{6} N$
C

$2 \times 10^{8} N$
D

$2 \times 10^{5} N$

Solution

$Y = \frac{F}{A} or F = Y \cdot A = 2 \times 10^{11} \times 10^{- 4} = 2 \times 10^{7} N$
if length is doubled, strain =1 and Y = stress

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