First slide

Elastic Modulie

Question

For steel $Y = 2 \times 10^{11} {Nm}^{- 2}$ then the force required to double the length of a steel wire of area 1 cm² is

Easy

A

2 X 10⁷ N
B

2 X 10⁶ N
C

2 X 10⁸ N
D

2 X 10⁵ N

Solution

$Y = \frac{F}{A} or F = Y \cdot A = 2 \times 10^{11} \times 10^{- 4} = 2 \times 10^{7} N$ if length is doubled strain =1 Y= stress

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