First slide

Relative motion based problems

Question

A stone is dropped from the top of a tower of height h. After 1s another stone is dropped from the balcony 20m below the top. Both reach the bottom simultaneously. What is the value of h? Take g=10 ms^-2.

Moderate

A

3125m
B

312.5m
C

31.25m
D

25.31m

Solution

$h = \frac{1}{2} {gt}^{2} and h - 20 = \frac{1}{2} g (t - 1)^{2}$
Solving them we get, t = 2.5 s and h = 31.25 m

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