A stone is dropped from the top of a tower of height ‘H’ ., in last second of its journey it covers a distance of  0.36 H. Then height H and time of fall  is g=10m/s2

Let ‘n’ is last sec Sn is distance in last secThen from  S=Ut+12at2,     H=0+12gn2--(1)Distance travelled before the last second is  H−0.36H=0.64H 0.64H=12gn−12 substitute H value from equation (1) ⇒0.64(12gn2)=12gn−12⇒0.64n2=n−12⇒64100n2=n−12⇒8n=10n−10⇒2n=10⇒n=5 The time of fall is 5sec  H=12gn2 ⇒H=121052 ⇒H=2502 H=125m=height of the tower