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Q.

A stone is dropped from the top of a tower. When it has fallen by 5 m from the top, another stone is dropped from a point 25 m below the top. Ifboth stones reach the ground at the same moment, then height of the tower is (take g = 10 m/s2)

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a

45 m

b

50 m

c

60 m

d

65 m

answer is A.

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Detailed Solution

Velocity of Ist stone when passing at AV2=0+2.10.5⇒V=10m/s and S1−S2=20m⇒ 10⋅t+1210⋅t2−12⋅10⋅t2=20 At t=2s,S2=12gt2=12×10×22=20mHence, height of the tower,H=S1+S2=25+20=45m

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