A stone falls freely under gravity. It covers a distance h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is
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a
h1=h23=h35
b
h2=3h,h3=3h2
c
h1=h2=h3
d
h1=2h2=3h3
answer is A.
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Detailed Solution
In first 5 second: h1=252g ..........1In second 5 second; h2=50g−252g=752g ..........2In third 5 second: h3=2252g−50g=1252g ..........3From (1) & (2) & (3)h1:h2:h3=1:3:5