First slide

Release from certain height

Question

A stone falls freely under gravity. It covers distances h₁ , h₂and h₃ in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h₁ , h₂ and h₃is :

Easy

A

h₁= h₂= h₃
B

h₁= 2h₂= 3h₃
C

$h_{1} = \frac{h_{2}}{3} = \frac{h_{3}}{5}$
D

h₂ - 3h₁ and h₃ = 3h₂

Solution

$h_{1} = \frac{1}{2} g {(5)}^{2}, h_{2} = \frac{1}{2} g {(10)}^{2} and h_{3} = \frac{1}{2} g {(15)}^{2}$
$\Rightarrow h_{1} = \frac{h_{2}}{3} = \frac{h_{3}}{5}$

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