A stone falls freely under gravity. It covers distances h1,h2 and h3in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1,h2 and h3 is
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a
h2=3h1 and h3=3h2
b
h1=h2=h3
c
h1=2h2=3h3
d
h1=h23=h35
answer is D.
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Detailed Solution
Distance covered by the stone in first 5 seconds(i.e. t = 5s) ish1=12g52=252g −−−iDistance travelled by the stone in next 5 seconds (i.e. t = 10 s) ish1+h2=12g102=1002g −−−iiDistance travelled by the stone in next 5 seconds (i.e. t =15 s) ish1+h2+h3=12g152=2252g −−−iiiSubtract (i) from (ii), we geth1+h2−h1=1002g−252g=752g h2=752g=3h1 −−−ivSubtract (ii) from (iii), we geth1+h2+h3−h2+h1=2252g−1002g h3=1252g=5h1 −−−vFrom (i), (iv) and (v), we geth1=h23=h35