A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The displacement (in meter) of the stone from the point of release after 10 sec is (Take g=10ms−2)

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answer is 620.

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Detailed Solution

Given : u=12m/s, g=10m/sec2,t=10sec Displacement =ut+12gt2=12×10+12×10×100=620m

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