A stone is hung in air from a wire which is stretched over a sonometer. The bridges of the sonometer are L cm apart when the wire is in unison with a tuning fork of frequency N. When the stone is completely immersed in water, the length between the bridges is l cm for $$re-establishing$$ unison, the specific gravity of the material of the stone is

Question

Infinity Learn · Accepted Answer

Frequency of vib. is stretched string $$n=12(Length)TmWhen$$ the stone is completely immersed in water, length changes but frequency doesn’t $$($$∵ unison $$reestablished)Hence$$ length ∝T⇒$$Ll=TairTwater=V$$ρ$$gV($$ρ−$$1)g(Density$$ of stone $$=$$ ρ and density of water $$=1)$$⇒$$Ll=$$ρρ−$$1$$⇒ρ$$=L2L2$$−$$l2$$

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