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Q.

A stone of mass 4 kg is fastened to one end of a steel wire of cross sectional area 1mm2 and is whirled in a horizontal circle of radius 50cm. If the breaking stress of steel is1.8×109Nm−2 . Find the maximum number of revolution the stone can make per second without the string breaking.

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a

4.77 rps

b

3.82 rps

c

2.43 rps

d

1.94 rps

answer is A.

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Detailed Solution

B.S=FA B.S=mrω2Aω2=B.S×Amr=1.8×109×10−64×50×10−2=900ω=30rad/s2πn=30n=302πrev/sec  = 4.77/sec1 rev=2πrad
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