A stone of mass 6 kg is revolved in a vertical circle of diameter 6m., such that its speed is minimum at a point. If the K.E at the same point is 250 J , then minimum PE at that point is

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200J

150J

100J

450J

answer is A.

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Detailed Solution

T.Ebutton=T.Ebutton ; 12m5gr2=P.E+K.E

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