Question

A stone is projected in air. Its time of flight is 3 s and range is 150 m. Maximum height reached by the stone is (Take, g = 10 ms^-2)

Moderate

Solution

Time of flight, $T = \frac{2 u_{y}}{g} = 3$
$∴ u_{y} = 15 m s^{- 1}$
Now, $H = \frac{u_{y}^{2}}{2 g} = \frac{(15)^{2}}{20} = 11.25 m$

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