Q.
A stone is projected from top of a vertical pole of height 3 m with initial velocity 10 ms-1. The maximum range on the ground is 10x m. The value of x is _____.
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answer is 4.
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Detailed Solution
Let stone is projected at an angle α with horizontal.∴ (ucosα)t= Range =R and −3=(10sinα)t−12×10×t2From Eqs. (i) and (ii), we getR2+5t2−32=100t2⇒R2+25t4+9−30t2=100t2⇒25t4−130t2+9+R2=0The discriminant of quadratic in t2 should be greater or equal to zero.∴ D≥0⇒ (−130)2−4×259+R2≥0⇒ 16900≥1009+R2⇒ 9+R2≤169⇒ 9+R2≤169⇒ R2≤160∴ R≤160∴ Rmax=410m∴ x=4
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