A stone is projected horizontally with speed v from a height h above ground. A horizontal wind is blowing in direction opposite to velocity of projection and gives the stone a constant horizontal acceleration f( in a direction opposite to initial velocity ). As a result the stone falls on ground at a point vertically below the point of projection. Then the value of height h in terms of f, g,v is (g is acceleration due to gravity)
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a
2gv2f2
b
gv22f2
c
gv2f2
d
2gv2f2
answer is A.
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Detailed Solution
Then taken to reach the ground is given by h=12gt2 ……..(1)Since horizontal displacement in time t is zerovelocity is reversed ∴t=2vf .......(2) From eq. (1) and (2) h=2gv2f2