First slide

Projection Under uniform Acceleration

Question

A stone is projected horizontally with a velocity of 40 m/s from a tower. Velocity of the body after 4 sec is (g=10 m/s²)

Easy

A

40 m/s
B

80 m/s
C

$40 \sqrt{2} m / s$
D

60 m/s

Solution

Horizontal velocity $40 \hat{i}$
Vertical velocity after $4 \sec \to 40 \hat{j}$
Velocity $= 40 \sqrt{2} m / s$

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