First slide

Vertical projection from ground

Question

A stone is projected up with a velocity of 98 m/sec. It reaches a point P in its path after 7 seconds. It reaches P again after another :

Easy

A

3 s.
B

13 s.
C

6 s.
D

9 s.

Solution

Time of flight $T = \frac{2 U}{g} = \frac{2 \times 98}{9 .8} = 20 \sec$
After 7 sec. it is at ‘h’. Then, again after
(20 - 7) = 13 sec. it will be at ‘h’.
Further time 13 - 7 = 6 sec.

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