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Q.

A stone is projected vertically up at 40 m/sec. The time interval between two points at which the stone is 60 m above the ground is g = 10 m/sec2)

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a

1 sec

b

2 sec

c

3 sec

d

4 sec

answer is D.

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Detailed Solution

h=Ut−12gt260=40t−1210t2t2 - 8t +12 = 0     t = 6 sec and t = 2 sec.time interval = 6 - 2 = 4 sec.
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A stone is projected vertically up at 40 m/sec. The time interval between two points at which the stone is 60 m above the ground is g = 10 m/sec2)