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Q.

A stone is projected with a velocity 202ms−1 at an angle of 450 to the horizontal. What will be the average velocity of stone during its motion from starting point to its maximum height? g=10ms−2

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a

55ms−1

b

105ms−1

c

20ms−1

d

205ms−1

answer is B.

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Detailed Solution

Refer figure are when projectile is at A, thenOC=R2=12u2gsin⁡2θ=12×(202)210sin2×45∘= 40AC=H=u2sin2⁡θ2g=(202)22×10sin2⁡45∘=20m∴ Displacement, OA=OC2+CA2=402+202Time of projectile from O to A=122usin⁡θg=usin⁡θ2g=(202)sin⁡45∘10=2s Average velocity = displacement  time =402+2022=105ms−1
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A stone is projected with a velocity 202ms−1 at an angle of 450 to the horizontal. What will be the average velocity of stone during its motion from starting point to its maximum height? g=10ms−2