A stone is projected with a velocity 202ms−1 at an angle of 450 to the horizontal. What will be the average velocity of stone during its motion from starting point to its maximum height? g=10ms−2
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a
55ms−1
b
105ms−1
c
20ms−1
d
205ms−1
answer is B.
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Detailed Solution
Refer figure are when projectile is at A, thenOC=R2=12u2gsin2θ=12×(202)210sin2×45∘= 40AC=H=u2sin2θ2g=(202)22×10sin245∘=20m∴ Displacement, OA=OC2+CA2=402+202Time of projectile from O to A=122usinθg=usinθ2g=(202)sin45∘10=2s Average velocity = displacement time =402+2022=105ms−1
A stone is projected with a velocity 202ms−1 at an angle of 450 to the horizontal. What will be the average velocity of stone during its motion from starting point to its maximum height? g=10ms−2