A stone projected with a velocity u angle θ with the horizontal reaches maximum height H1. When it is projected with velocity u at an angle π2−θ with the horizontal, it reaches maximum height H2. The relation between the horizontal range R of the projectile, H1 and H2 is
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a
R=4H1H2
b
R=4H1−H2
c
R=4H1+H2
d
R=H12H22
answer is A.
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Detailed Solution
H1=u2sin2θ2g and H2=u2sin2(90−θ)2g=u2cos2θ2gH1H2=u2sin2θ2g×u2cos2θ2g=u2sin2θ216g2=R216∴ R=4H1H2