Questions
A stone is thrown at an angle to the horizontal reaches a maximum height H. Then the time of flight of stone will be:
a
2Hg
b
22Hg
c
22H sin θg
d
2H sin θg
detailed solution
Correct option is B
H = u2sin2θ2g and T = 2u sin θgor T2 = 4u2 sin2θg2 T2H= (4u2sin2θg)×2gu2sin2θ = 8gor T2 = 8Hg ⇒ T = 22HgTalk to our academic expert!
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