Questions
A stone is thrown at an angle with the horizontal, reaches a maximum height H. Then, the time of flight of stone will be
a
2Hg
b
22Hg
c
22Hsinθg
d
2Hsinθg
detailed solution
Correct option is B
H=u2sin2θ2g and T=2usinθg⇒T2=4u2sin2θg2∴ T2H=8g⇒T=8Hg=22HgTalk to our academic expert!
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