Question

A stone is thrown at an angle $θ$ with the horizontal, reaches a maximum height H. Then, the time of flight of stone will be

Moderate

Solution

$H = \frac{u^{2} \sin^{2} θ}{2 g} and T = \frac{2 u \sin θ}{g} \Rightarrow T^{2} = \frac{4 u^{2} \sin^{2} θ}{g^{2}}$
$∴ \frac{T^{2}}{H} = \frac{8}{g} \Rightarrow T = \sqrt{\frac{8 H}{g}} = 2 \sqrt{\frac{2 H}{g}}$

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