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Q.

A stone is thrown at an angle θ with the horizontal, reaches a maximum height H. Then, the time of flight of stone will be

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a

2Hg

b

22Hg

c

22Hsinθg

d

2Hsinθg

answer is B.

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Detailed Solution

H=u2sin2θ2g and T=2usinθg⇒T2=4u2sin2θg2∴  T2H=8g⇒T=8Hg=22Hg
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